What is ${(2 p^{- 3})}^{5}$ $(2p^-3)^5$ ?

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What is ${(2 p^{- 3})}^{5}$ $(2p^-3)^5$ ?

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Answer 1 · 2016-03-30T05:04:44

$\frac{32}{p^{15}}$ $32/p^15$

Explanation:

${(a b)}^{n} = a^{n} b^{n} and a^{- m} = \frac{1}{a^{m}}$ $(ab)^n=a^nb^n and a^(-m)=1/a^m$ . Also, ${(a^{m})}^{n} = a^{m n}$ $(a^m)^n=a^(mn)$
${(2 p^{- 3})}^{5} = 2^{5} {(p^{- 3})}^{5} = 32 p^{- 15} = \frac{32}{p^{15}}$ $(2p^(-3))^5=2^5(p^(-3))^5=32p^(-15)=32/p^15$ .

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What is ${(2 p^{- 3})}^{5}$ $(2p^-3)^5$ ?

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