How do you solve $s + - 12 = 208$ $s + -12 = 208$ ?

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Answer 1 · 2016-03-31T08:28:56

$s = 220$ $s=220$

The equation is:

$s - 12 = 208$ $s-12=208$

Therefore, adding 12 to both sides

$scancel(-12)cancel(+12)=208+12$

$s=220$

This will be the answer.

How do you solve s + -12 = 208s+−12=208s + -12 = 208?