Question

How do you find the derivative of `xsqrt(2x - 3)`?

Answer 1

`f'(x)= (3(x-1))/sqrt(2x-3)`

Explanation:

Using product rule `f=uv => f'=u'v+uv'`, we have:

`f'(x)= (xsqrt(2x-3))'=1*sqrt(2x-3)+x*1/(2sqrt(2x-3))*2`

`f'(x)= sqrt(2x-3)+x/sqrt(2x-3)`

`f'(x)= (3x-3)/sqrt(2x-3)`

`f'(x)= (3(x-1))/sqrt(2x-3)`