How do you find #abs( 1-isqrt3 )#? Precalculus Complex Numbers in Trigonometric Form Complex Number Plane 1 Answer Alexander L. Apr 2, 2016 #4# Explanation: Sum the squares of all the numbers: #1^2+(-sqrt3)^2=1+3=4# Answer link Related questions What is the complex number plane? Which vectors define the complex number plane? What is the modulus of a complex number? How do I graph the complex number #3+4i# in the complex plane? How do I graph the complex number #2-3i# in the complex plane? How do I graph the complex number #-4+2i# in the complex plane? How do I graph the number 3 in the complex number plane? How do I graph the number #4i# in the complex number plane? How do I use graphing in the complex plane to add #2+4i# and #5+3i#? How do I use graphing in the complex plane to subtract #3+4i# from #-2+2i#? See all questions in Complex Number Plane Impact of this question 1719 views around the world You can reuse this answer Creative Commons License