How do you solve $5 x^{3} - 320 x = 0$ $5x^3 - 320 x = 0$ ?

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Answer 1 · 2016-04-08T16:52:47

$x = \pm 8$ $x=±8$

$5 x^{3} - 320 x = 0$ $5x^3-320x=0$

$cancel(5)cancel(x)^3=cancel(320)cancel(x)$

$x^2=64$

$sqrt (x^2)=sqrt64$

$sqrt(x^2)=sqrt 8^2$

$x=±8$

How do you solve 5x^3 - 320 x = 05x3−320x=0 5x^3 - 320 x = 0?