Question

How do you solve `x^2-5x+4=0`?

Answer 1

`x=4` or `x=1`

Explanation:

`x^2-5x+4=0`

We need to factorize it:

`x^2-x-4x+4=0`

`x(x+1)-4(x-1)=0`

`(x-4)(x-1)=0`

`x-4=0` or `x-1=0`

`x=4` or `x=1`