How do you factor #1/4x^2-4#?

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Answer 1 · 2016-04-09T18:01:19

#(x/2+2)(x/2-2)#

We will use the following property to find the factors of the given expression:

#a^2-b^2=(a+b)(a-b)#

Solution:

#1/4x^2-4#

Here, #a^2=1/4x^2# and #b^2=4#

#=>a=1/2x# and #b = 2#

#1/4x^2-4=(x/2+2)(x/2-2)#