How do you evaluate #ln sqrt(e)#?

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Answer 1 · 2016-04-10T07:06:00

#1/2#

Recall that: #sqrtn=n^(1/2:#

We can now express your equation as:
#lnsqrte=lne^(1/2)#

Recall that: #log_na^m=mlog_na#

We can further simplify the given equation:

#lne^(1/2)=1/2lne#

Recall that: #lne=log_ee=1#

We can now say that:

#1/2lne=1/2(1)=1/2#

Therefore, #lnsqrte=1/2#