How do you simplify #(b^3 a^5)/(b^2 a^4)#?
2 Answers
Apr 10, 2016
Explanation:
So you should cancel b's and a's in nominator and denominator. So the result would be
More scientifically:
Apr 10, 2016
ab
Explanation:
Using the following
#color(blue)" rule of exponents " #
#color(red)(|bar(ul(color(white)(a/a)color(black)( a^m/a^n hArr a^(m-n))color(white)(a/a)|)))#
#rArr (b^3a^5)/(b^2a^4) = b^3/b^2xxa^5/a^4 = b^(3-2)xxa^(5-4) = ab#