Question #3686f

1 Answer
Apr 19, 2016

5 multiple choice

Explanation:

The best thing to do when dealing with hard and annoying math problems is take away the fluff and identify all the important info:

  • 60 points total
  • 15 questions total
  • Multiple choice questions are two points each
  • Open-ended are five points each

So, what don't we know? We don't know how many open-ended and multiple choice questions there are, and that's what we're trying to find. And what do we do when we don't know something? Assign it a variable! We'll have the number of open-ended questions be O and the number of multiple-choice questions be M.

Because there are only two types of questions and 15 questions total, we know that the number of open-ended questions plus the number of multiple choice questions is 15:
O+M=15

And we also know that there are 60 points total. If multiple-choice questions are two points each, that means the total number of points for answering multiple choice questions correctly is 2M. For example, if you get 10 multiple-choice questions right, the number of points you get is 2*10=20 points. Likewise, the number of points for open-ended questions is 5O. The key is that there are 60 points in all, so the amount of points you get from multiple choice plus the amount of points you get from open-ended must be 60:
2M+5O=60

Let's see. It appears we have the system:
O+M=15
5O+2M=60

We are being asked for the number of multiple-choice questions, so we have to solve this system for M. To do this, first solve for O in terms of M:
O+M=15->O=15-M

Now substitute this for O in 5O+2M=60 and solve:
5O+2M=60
5(15-M)+2M=60
75-5M+2M=60
-3M=-15
M=5

That means there are 5 multiple-choice questions on the test, and 15-5=10 open-ended. This makes sense because if each open-ended question is 5 points, then you can get 50 points max (10*5), and if there are 5 multiple-choice questions, then you can get 10 points max (5*2). The total number of points you can get is therefore 60, which is what we were told at the beginning.