Question

How do you solve `4 x^2 – 3x + 3 = 0` using the quadratic formula?

Answer 1

`x=(-b+-sqrt(b^2-4ac))/(2a)`

Explanation:

First identify `a,b,c`

`ax^2+bx+c=f_x`

By looking at `4x^2-3x+3`
`a=4`
`b=3`
`c=3`

Now just plug it in and solve

`x=(-3+-sqrt(3^2-4(4)(3)))/(2(4))`