How do you solve $4 x^2 – 3x + 3 = 0$ using the quadratic formula?

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Answer 1 · 2016-04-20T20:52:22

$x=(-b+-sqrt(b^2-4ac))/(2a)$

First identify $a,b,c$

$ax^2+bx+c=f_x$

By looking at $4x^2-3x+3$
$a=4$
$b=3$
$c=3$

Now just plug it in and solve

$x=(-3+-sqrt(3^2-4(4)(3)))/(2(4))$

How do you solve 4 x^2 – 3x + 3 = 04 x^2 – 3x + 3 = 0 using the quadratic formula?