How do you solve $- 4 (x - 3) - 20 = - 8$ $-4(x-3) - 20 = -8$ ?

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Answer 1 · 2016-04-21T17:30:34

$x = 0$ $x=0$

solve the bracket first according to bodmas
$- 4 x + 12 - 20 = - 8$ $-4x+12-20=-8$
$- 4 x = - 8 + 8$ $-4x=-8+8$
$- 4 x = 0$ $-4x=0$
$x = 0$ $x=0$

How do you solve −4(x−3)−20=−8-4(x-3) - 20 = -8?