Question #d71a4
1 Answer
Apr 25, 2016
Explanation:
First consider how the compound will dissolve in water - or rather, how it dissociates into its smaller ionic components due to it being an ionic compound,
On the left of the equation is the reactant, and on the right, the products. The reactant is a solid, so it will not be included in the solubility equation.
In one mole of