How do you solve the following system?: $4 x - 5 y = 5, 7 y = 4 - 2 x$ $4x-5y=5 , 7y=4- 2x$

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Answer 1 · 2016-04-30T13:10:28

x = $\pm$ $+-$ 1.35 ; y = $\pm$ $+-$ 0.18.

$4 x - 5 = 5 y$ $4x-5=5y$ , $y = 0.8 x - 1$ $y=0.8x-1$ .
$y = \frac{- 2 x}{7} + \frac{4}{7}$ $y=(-2x)/7+4/7$ .

graph{(y-0.8x+1)(y+2/7x-4/7)=0 [-1, 4, -1.25, 1.25]} .

x = $\pm$ $+-$ 1.35 ; y = $\pm$ $+-$ 0.18.

JUST SHOWING HOW GRAPHS ARE USEFUL.

How do you solve the following system?: 4x−5y=5,7y=4−2x 4x-5y=5 , 7y=4- 2x