How do you graph $3 x - 4 y = - 12$ $3x-4y=-12$ using the intercepts?

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Answer 1 · 2016-05-03T19:15:49

If you know the $x -$ $x-$ and $y -$ $y-$ intercepts of a line you can draw the line passing through them.

All along the $x -$ $x-$ axis, $y$ $y$ = 0. All along the $y -$ $y-$ axis, $x$ $x$ = 0.

To find the $x$ $x$ intercept, make $y$ $y$ = 0 and solve for $x$ $x$ .
To find the $y$ $y$ intercept, make $x$ $x$ = 0 and solve for $y$ $y$ .

In this example:

For the $x$ $x$ intercept, $3 x - 4 (0) = - 12$ $3x - 4(0) = -12$ $\Rightarrow x = - 4$ $rArr x = -4$

For the $y$ $y$ intercept, $3 (0) - 4 y = - 12$ $3(0) - 4y =-12$ $\Rightarrow y = 3$ $rArr y = 3$ graph graph{y = 3x/4 +3 [-10, 10, -5, 5]}

Draw the line through these points.

How do you graph 3x−4y=−123x-4y=-12 using the intercepts?