What is the slope and intercept of #2y = -5#?

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Answer 1 · 2016-05-04T01:58:33

The slope is 0.

Consider the general equation of a straight line:

#y=mx+c#

Where #m# refers to the value of the function's slope.

Let's now rearrange your equation to this general form:

#(2y)/2=-5/2#

#y=-5/2#

Therefore, we can see that no #x# coefficient exists. This is to say that:

#y=-5/2=0x-5/2#

This implies that no slope exists, and the graph instead exists parallel to the #x# axis.