Question #ab32b

1 Answer
Madi
May 6, 2016

#2/sqrt(3)# or #(2sqrt3)/3#

Explanation:

#sec (pi/6) = 1/ (cos (pi/6))#

#cos (pi/6) = sqrt (3)/2#

#1/(sqrt(3)/2) = 2/sqrt3#

Rationalize the denominator by multiplying the numerator and denominator by #sqrt3#

#2/sqrt(3) * sqrt3/sqrt3 = (2sqrt3)/3#

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