What is the temperature of 350 mL of gas at .85 atm if it has a volume of 920 mL at STP?

Question

2147 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-07T02:47:56

$88.3K$

Use the equation:

$(P_1 * V_1)/(T_1) = (P_2*V_2)/T_2$

Where $P_1$ is the pressure at STP, $T_1$ is the temperature at STP and $V_1$ is $0.92L$ .

Substitute all the values in.

$[(1 atm)(0.92L)]/(273K) = [(0.85atm)(0.35L)]/T_2$

$(T_2)(0.92L)= (273K)(0.85atm)(0.35L)$

$(T_2)(0.92L)= 81.22$

$(T_2) = 88.3K$