Question

How many moles of `CaCl_2` are in 250 mL of a 3.0 M of `CaCl_2` solution?

Answer 1

`0.75`mol

Explanation:

`C = (n\ mol)/V`, where `C` is concentration, `n` is number of moles and `V` is volume in liters.

In this problem, `C = 3.0 M` and `V = 0.25L`

Substitute this into the equation.

`3.0M = (n\ mol)/(0.25L)`

`3.0 ((mol)/cancel(L)) * 0.25cancel(L) = 0.75\ mol`