How do you solve $3x^2 + 2x - 5 = 0$ ?

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Answer 1 · 2016-05-07T06:43:10

$(3x + 5) = 0$

$x= - (5/3)$

$x - 1 = 0$
$x= 1$

Hence, solution is $x = -(5/3) or x=1$

The question gives you an equation $3x^2 + 2x -5 = 0$ .

Hence to solve the equation, factorise.

$3x^2 + 2x -5 = 0$
$(3x + 5)(x -1) = 0$

The 2 factors of the equation are $(3x + 2) and (x - 1).$

With $(3x + 5) = 0$ and $(x - 1) = 0$
Solve for $x$ to find the solutions.

How do you solve 3x^2 + 2x - 5 = 03x^2 + 2x - 5 = 0?