How do you calculate ${log}_{5} 25$ $log_5 25$ ?

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How do you calculate ${log}_{5} 25$ $log_5 25$ ?

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Answer 1 · 2016-05-09T22:58:36

$2$ $2$

Explanation:

$log 5 (25)$ $log5(25)$ can be rewritten as
$log 5 {(5)}^{2}$ $log5(5)^2$ which is further simplified by the laws of logarithm to
$2 log 5 (5)$ $2log5(5)$ .

$log 5 (5) = 1$ $log5(5)=1$
Hence,
$2 log 5 (5) = 2 \cdot (1) = 2$ $2log5(5)=2*(1)=2$

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How do you calculate ${log}_{5} 25$ $log_5 25$ ?

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