Question

How do you solve `5x^2-40x+80=0`?

Answer 1

I think the answer is -5.3.

Explanation:

`5x^2-40x+80 =0`

`5x*5x=25x` Take care of the exponent first.

`25x-40x+80=0` Solve the like terms.

`-15x+80=0` Carry 80 over.

`-15x/-15=80/-15` Cancel out -15 and divide 80 by that same number.

`x=-5.3` Plug in the answer you get and round it to the nearest ten.