What is the heat capacity of a piece of wood if 1500 g of the wood absorbs 67,500 joules of heat, and its temperature changes from 32°C to 57°C?

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Answer 1 · 2016-05-13T09:37:13

#Q=m*c*Delta t#

The amount of heat absorbed is given by:

#Q=m*c*Delta t#

Where:

#m " is the mass of the wood"#
#c " is the specific heat capacity"#
#Deltat " is the change in temperature"#

Solve for c;

#c=Q/(m*Deltat"#

#c=(67500J)/(1500g*25^oC)#

#c= 1.8 J/g^oC#