Question #907e5

Question

2200 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-13T12:27:29

$-40^o$

Note the conversion formula:

$C/5 = (F-32)/9.......(1)$

We are required to find such an $x$ such that $C=x=F$ . Lets try putting this on relation $(1)$ :

$x/5 = (x-32)/9$

$=>9x = 5x-160$

$=>4x = -160$

$=> x = -40$

Hence, $-40^oC = -40^oF$