An adult has 206 bones. Of those, approximately 2.9% are found in the inner ear. About how many bones in the human body are found in the inner ear?

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An adult has 206 bones. Of those, approximately 2.9% are found in the inner ear. About how many bones in the human body are found in the inner ear?

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Answer 1 · 2016-05-14T04:19:24

$6$ $6$ bones

Explanation:

The two steps to solving this problem are:

$1$ $1$ . Converting $2.9 %$ $2.9%$ into a fraction.
$2$ $2$ . Multiplying the fraction form of $2.9 %$ $2.9%$ by the total number of bones in the human body.

Rewriting 2.9% as a Fraction
Since $%$ $%$ means "out of hundred," put $2.9$ $2.9$ over $100$ $100$ .

$2.9 %$ $2.9%$

$= \frac{2.9}{100}$ $=2.9/100$

As there cannot be any decimals in a fraction, you must get rid of the decimal. You do this by multiplying the numerator and denominator by $10$ $10$ .

$= \frac{2.9}{100} (\frac{10}{10})$ $=2.9/100(10/10)$

$= \frac{29}{1000}$ $=29/1000$

Determining the Number of Bones Found in the Inner Ear
Multiply $206$ $206$ bones by $\frac{29}{1000}$ $29/1000$ .

$206 i bones \cdot \frac{29}{1000}$ $206color(white)(i)"bones"*29/1000$

Since $206$ $206$ and $1000$ $1000$ can be divided by a common factor of $2$ $2$ , their values are reduced.

$= 206 \div 2 i bones \cdot \frac{29}{1000 \div 2}$ $=206color(red)(-:2)color(white)(i)"bones"*29/(1000color(red)(-:2))$

$= 103 i bones \cdot \frac{29}{500}$ $=103color(white)(i)"bones"*29/500$

Solve.

$= 5.974 i bones$ $=5.974color(white)(i)"bones"$

$~~color(green)(|bar(ul(color(white)(a/a)color(black)(6color(white)(i)"bones")color(white)(a/a)|)))$

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An adult has 206 bones. Of those, approximately 2.9% are found in the inner ear. About how many bones in the human body are found in the inner ear?

1 Answer

Explanation:

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