How do you simplify #sqrt 8 + sqrt2#?

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Answer 1 · 2016-05-14T13:24:42

3#sqrt(2)#

start off by simiplying the #sqrt(8)# :

#sqrt(8)# = #sqrt(4*2)#

#sqrt(4)# = 2

therefore #sqrt(8)# = 2#sqrt(2)#

2#sqrt(2)# + #sqrt(2)#

= 3#sqrt(2)#

Answer 2 · 2016-05-14T13:25:31

Well it is

#sqrt8+sqrt2=sqrt(2^2*2)+sqrt2=2sqrt2+sqrt2=3*sqrt2#