How do you simplify $\sqrt{8} + \sqrt{2}$ $sqrt 8 + sqrt2$ ?

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How do you simplify $\sqrt{8} + \sqrt{2}$ $sqrt 8 + sqrt2$ ?

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Answer 1 · 2016-05-14T13:24:42

3 $\sqrt{2}$ $sqrt(2)$

Explanation:

start off by simiplying the $\sqrt{8}$ $sqrt(8)$ :

$\sqrt{8}$ $sqrt(8)$ = $\sqrt{4 \cdot 2}$ $sqrt(4*2)$

$\sqrt{4}$ $sqrt(4)$ = 2

therefore $\sqrt{8}$ $sqrt(8)$ = 2 $\sqrt{2}$ $sqrt(2)$

2 $\sqrt{2}$ $sqrt(2)$ + $\sqrt{2}$ $sqrt(2)$

= 3 $\sqrt{2}$ $sqrt(2)$

Answer 2 · 2016-05-14T13:25:31

Well it is

$\sqrt{8} + \sqrt{2} = \sqrt{2^{2} \cdot 2} + \sqrt{2} = 2 \sqrt{2} + \sqrt{2} = 3 \cdot \sqrt{2}$ $sqrt8+sqrt2=sqrt(2^2*2)+sqrt2=2sqrt2+sqrt2=3*sqrt2$

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How do you simplify $\sqrt{8} + \sqrt{2}$ $sqrt 8 + sqrt2$ ?

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