How do you simplify #log_2 14 - log_2 7#? Precalculus Properties of Logarithmic Functions Common Logs 1 Answer Nicole · Jim H May 14, 2016 #log_2(14) - log_2(7) = 1# Explanation: Using the log rule #log_x(a) – log_x(b) = log_x(a/b)# Rewrite the equation as: #log_2(14/7)# = #log_2(2)# Use the log rule: #log_x(x)# = 1 Therefore #log_2(2)# = 1 So #log_2(14) - log_2(7) = 1# Answer link Related questions What is the common logarithm of 10? How do I find the common logarithm of a number? What is a common logarithm or common log? What are common mistakes students make with common log? How do I find the common logarithm of 589,000? How do I find the number whose common logarithm is 2.6025? What is the common logarithm of 54.29? What is the value of the common logarithm log 10,000? What is #log_10 10#? How do I work in #log_10# in Excel? See all questions in Common Logs Impact of this question 7147 views around the world You can reuse this answer Creative Commons License