Question #eebf3

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Question #eebf3

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Answer 1 · 2016-05-15T02:57:00

$0.179$ $0.179$ $M$ $M$

Explanation:

The way to find this is given by the formula $M_{1} V_{1} = M_{2} V_{2}$ $M_1V_1 = M_2V_2$ for titrations

Therefore, the sulfuric acid is $0.3$ $0.3$ $M$ $M$ and $25$ $25$ $m L$ $mL$ as Volume
i.e. $M_{1} = 0.3$ $M_1 = 0.3$ $M$ $M$ , $V_{1} = 25$ $V_1 = 25$ $m l$ $ml$ ; $V_{2} = 42$ $V_2 = 42$ $m l$ $ml$ ; $M_{2} = ?$ $M_2 =?$

$0.3 \times 25 = 42 \cdot x$ $0.3 xx 25 = 42 * x$
where $x$ $x$ is the molarity of sodium hydroxide

$7.5 = 42 x$ $7.5 = 42x$

$x = 0.17857$ $x = 0.17857$ $M$ $M$

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Question #eebf3

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