What is the equation of the line passing through $(- 1, 4)$ $(-1,4)$ and $(- 2, 3)$ $(-2,3)$ ?

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Answer 1 · 2016-05-15T09:47:03

$y = x + 5$ $y = x + 5$

First you find the gradient of the line using the formula $\frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $(y_2-y_1)/(x_2-x_1)$

$\frac{3 - 4}{- 2 - - 1}$ $(3-4)/(-2--1)$ = $\frac{- 1}{- 1}$ $(-1)/(-1)$ = $1$ $1$

Next, use the equation of a line which is

$(y - y_{1}) = m (x - x_{1})$ $(y-y_1) = m(x-x_1)$ , where m is the gradient

$(y - 4) = 1 (x - - 1)$ $(y-4) = 1(x--1)$

= $y - 4 = x + 1$ $y-4 = x+1$

Therefore

$y = x + 5$ $y = x + 5$

What is the equation of the line passing through (-1,4)(−1,4)(-1,4) and (-2,3)(−2,3)(-2,3)?