What is the equation of the line passing through #(-1,4)# and #(-2,3)#?

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Answer 1 · 2016-05-15T09:47:03

#y = x + 5#

First you find the gradient of the line using the formula #(y_2-y_1)/(x_2-x_1)#

#(3-4)/(-2--1)# = #(-1)/(-1)# = #1#

Next, use the equation of a line which is

# (y-y_1) = m(x-x_1) # , where m is the gradient

#(y-4) = 1(x--1)#

= #y-4 = x+1#

Therefore

#y = x + 5 #