What is the moment of inertia of a pendulum with a mass of $7 k g$ $7 kg$ that is $4 m$ $4 m$ from the pivot?

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What is the moment of inertia of a pendulum with a mass of $7 k g$ $7 kg$ that is $4 m$ $4 m$ from the pivot?

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Answer 1 · 2016-05-16T18:22:27

$m o m e n t = 280 N m$ $moment=280 Nm$

Explanation:

first of all convert $7 k g$ $7kg$ into Newtons by multiplying by $10$ $10$ as it is the gravitational force.
so $7 \cdot 10 = 70 N$ $7*10=70N$
now apply the formula
$m o m e n t = N \cdot d$ $moment= N *d$
$m o m e n t = 70 \cdot 4$ $moment=70*4$
$m o m e n t = 280 N m$ $moment=280 Nm$

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What is the moment of inertia of a pendulum with a mass of $7 k g$ $7 kg$ that is $4 m$ $4 m$ from the pivot?

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What is the moment of inertia of a pendulum with a mass of $7 k g$ $7 kg$ that is $4 m$ $4 m$ from the pivot?