A car is traveling at a constant speed of 12 m/s. When the driver accelerates, the car reaches a speed of 26 m/s in 6 s. What is the average acceleration of the car?

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A car is traveling at a constant speed of 12 m/s. When the driver accelerates, the car reaches a speed of 26 m/s in 6 s. What is the average acceleration of the car?

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Answer 1 · 2016-05-17T06:33:07

$a = \frac{7}{3}$ $a=7/3$ $m$ $m$ / $s^{2}$ $s^2$

Explanation:

So the suvat equations are needed here, or rather one in particular:

$v = u + a t$ $v=u+at$

(Where $u$ $u$ is initial speed, $v$ $v$ is final speed, $a$ $a$ is acceleration and $t$ $t$ is time).

This can be rearranged (to get $a$ $a$ ):

$a t = v - u$ $at=v-u$

$a = \frac{v - u}{t}$ $a=(v-u)/t$

Since $u$ $u$ is $12$ $12$ $m$ $m$ / $s$ $s$ , $v$ $v$ is $26$ $26$ $m$ $m$ / $s$ $s$ and $t$ $t$ is $6$ $6$ $s$ $s$ :

$a = \frac{26 - 12}{6}$ $a=(26-12)/6$

$a = \frac{14}{6}$ $a=14/6$

$a = \frac{7}{3}$ $a=7/3$ $m$ $m$ / $s^{2}$ $s^2$

These are the equations of motion if you'd like to use them without further proof: (they only work for constant acceleration, variable acceleration needs calculus).

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A car is traveling at a constant speed of 12 m/s. When the driver accelerates, the car reaches a speed of 26 m/s in 6 s. What is the average acceleration of the car?

1 Answer

Explanation:

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