Question

Question #3f2c0

Answer 1

`P.MM= d.R.T`

Explanation:

Use the ideal gas equation

`P.V=n.R.T`

`P.V= m/(MM).R.T`

`P.MM= m/V.R.T`

`P.MM= d.R.T`

`P" is the pressure of the gas (" atm")"`
`MM" is the molar mass ("g.mol^-1")"`
`d" is the density of the gas ("g.L^-1")"`k
`R" is the universal gas constant ("0.0821L.\atm.mol^-1.K^-1")"`

Solve for `MM`

`MM= (d.R.T)/P`

`MM= (1.8g.L^-1*0.0821L*\atm*mol^-1*K^-1*300.*K)/((760mmHg*(1.\atm)/(760*mmmHg))`

`MM ~= 44 " "g.mol^-1`