A circuit with a resistance of $6 Omega$ has a fuse that melts at $8 A$ . Can a voltage of $49 V$ be applied to the circuit without blowing the fuse?

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Answer 1 · 2016-05-19T00:16:22

The fuse will blow out.

$"Current"= "voltage"/"Resistance"$
i.e. $I =V/R$
so current is $49/6$ = $8.16$ $A$
As current in circuit is $8.16$ $A$ fuse will blow out.

A circuit with a resistance of 6 Omega6 Omega has a fuse that melts at 8 A8 A. Can a voltage of 49 V49 V be applied to the circuit without blowing the fuse?