Question

A circuit with a resistance of `6 Omega` has a fuse that melts at `8 A`. Can a voltage of `49 V` be applied to the circuit without blowing the fuse?

Answer 1

The fuse will blow out.

Explanation:

`"Current"= "voltage"/"Resistance"`
i.e. `I =V/R`
so current is `49/6`= `8.16` `A`
As current in circuit is `8.16` `A` fuse will blow out.