How do you solve $- \frac{3}{4} x = 12$ $-3/4 x = 12$ ?

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How do you solve $- \frac{3}{4} x = 12$ $-3/4 x = 12$ ?

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Answer 1 · 2016-05-19T13:14:57

convert $- \frac{3}{4}$ $-3/4$ into a decimal, then divide $\frac{12}{- 0.75}$ $12/-0.75$

Explanation:

$- \frac{3}{4} = 3 \div 4 = - 0.75$ $-3/4= 3-:4=-0.75$

$\frac{12}{- 0.75} = - 16$ $12/-0.75=-16$

$x = - 16$ $x=-16$

Because $- 0.75 \times - 16 = 12$ $-0.75xx-16=12$

Answer 2 · 2016-05-19T13:21:47

$x = - 16$ $x=-16$

Explanation:

Multiply both sides by $\frac{4}{3}$ $color(blue)(4/3)$

$- \frac{3}{4} x = 12 \to - (\frac{3}{4} \times \frac{4}{3}) \times x = 12 \times \frac{4}{3}$ $color(brown)(-3/4x=12" "->" "-(3/4color(blue)(xx4/3))xx x= 12color(blue)(xx4/3))$

But $\frac{3}{4} \times \frac{4}{3} = 1$ $3/4xx4/3 = 1$

$- 1 \times x = 16$ $-1xx x=16$

Multiply both sides by $(- 1)$ $(-1)$

$+ 1 \times x = - 16$ $+1xx x = -16$

$x = - 16$ $x=-16$

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How do you solve $- \frac{3}{4} x = 12$ $-3/4 x = 12$ ?

2 Answers

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