How do you solve #5y – x – 6 = 0# and #-3x + 6y = -9#?
1 Answer
May 19, 2016
Explanation:
First Method, using substitution
By rearranging the first equation we have,
substitute value of
by substituting value of
we have
Second Method,
Multiply first equation with 3,
Now subtract LHS of the second equation from the LHS above equation and do the same with the RHS,
and by substituting