Question

How do you solve `x^2 - 3x + 1 = 0`?

Answer 1

`(3±sqrt(5))/(2)`

Explanation:

Use the quadratic formula

`(-b±sqrt(b^2-4ac))/(2a)`

`a=1`
`b=-3`
`c=1`

`(3±sqrt(-3^2-4xx1xx1))/(2xx1)` = `(3±sqrt(5))/(2)`