How do you write the standard form of a line given (3,11) and (-6, 5)?

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Answer 1 · 2016-05-20T13:46:10

#-2x+3y=27#

First find the gradient (m) , which is #(y_2-y_1)/(x_2-x_1)#

#(5-11)/(-6-3)# = #2/3#

Next find the equation of the line using #(y-y_1)=m(x-x_1)#

#y-5=2/3(x+6)#

#3y-15=2x+12#

The standard form of line is one in the form #Ax+By=C#

Therefore, #-2x+3y=27#