How do you factor # 2x^2 - 5x - 3#?

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Answer 1 · 2016-05-21T08:17:30

#(2x + 1)(x-3)#

Multiply a and c. Find two numbers that add to b and multiply to ac

#2 * -3 = -6#

#-6 + 1 = -5#
#-6 *1 = -6#

Re-write equation with these numbers
# 2x^2 -6x +x -3#

Factorise that equation
#2x(x-3) +1(x-3)#

Therefore the answer is;

#(2x + 1)(x-3)#