How do you simplify #4a(5a - 2)#?

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Answer 1 · 2016-05-21T15:52:02

#a=0#

#a=2/5#

Expand the brackets:

#20a^2 -8a#

#a(20a-8)#

You can then solve the equation to find #a#.

#a=0#

#a=8/20=2/5#

Or, you could solve the equation directly from the question.