If a horizontal component of force $F_{x} = 25.0$ $F_x=25.0$ $N$ $N$ and a vertical component of force $F_{y} = 15.0$ $F_y = 15.0$ $N$ $N$ , what is the resultant force?

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If a horizontal component of force $F_{x} = 25.0$ $F_x=25.0$ $N$ $N$ and a vertical component of force $F_{y} = 15.0$ $F_y = 15.0$ $N$ $N$ , what is the resultant force?

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Answer 1 · 2016-05-24T16:47:52

$29.15 N$ $29.15 N$

Explanation:

Forces add like vectors. Since the angle between these two forces is 90º we can simply use the pythagorean theorem and think of them as two sides of a right triangle.

$F_{net} = \sqrt{F_{x}^{2} + F_{y}^{2}}$ $F_("net") = sqrt(F_x^2 + F_y^2)$

$F_{net} = \sqrt{25^{2} + 15^{2}}$ $F_("net") = sqrt(25^2 + 15^2)$

$F_{net} = \sqrt{625 + 225}$ $F_("net") = sqrt(625 + 225)$

$F_{net} = \sqrt{850}$ $F_("net") = sqrt(850)$

$F_{net} = 29.15 N$ $F_("net") = 29.15 N$

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If a horizontal component of force $F_{x} = 25.0$ $F_x=25.0$ $N$ $N$ and a vertical component of force $F_{y} = 15.0$ $F_y = 15.0$ $N$ $N$ , what is the resultant force?

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Explanation:

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Science

Math

Humanities

... and beyond

If a horizontal component of force Fx=25.0F_x=25.0 NN and a vertical component of force Fy=15.0F_y = 15.0 NN, what is the resultant force?

1 Answer

Explanation:

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If a horizontal component of force $F_{x} = 25.0$ $F_x=25.0$ $N$ $N$ and a vertical component of force $F_{y} = 15.0$ $F_y = 15.0$ $N$ $N$ , what is the resultant force?