Question #9abd1

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Answer 1 · 2016-05-25T18:44:49

$"The vertex will be at the point " (-1, \ 4)$

$"Rearrange the formula so that it fits the parabola equation"$

$y= a( x- h)^2+k$

$"The vertex will be at the point" (\ h, \ k)$

$"To rearrange the equation, add one and subtract one"$

$y=-x^2-2x-color(red)1+3+color(red)1$

$y=(-x^2-2x-color(red)1)+3+color(red)1$

$y=-1*(x^2+2x+1)+4$

$y=-1*(x+1)^2+4$

$y=-1*(x-(color(red)(-1)))^2+color(red)4$

$h=-1 " and " k=4$

$"The vertex will be at the point " (-1, \ 4)$

$""$

$"The " x "- intercept is at " x=-3 " and " x=1 "$

$"The " y "- intercept is at " y=3$

graph{-x^2-2*x+3 [-8.77, 6.94, -2.18, 5.675]}