How many milliliters of 12.0 M hydrochloric acid ( $H C l$ $HCl$ ) is required to prepare 0.75 L of a 0.25 M solution of $H C l$ $HCl$ ?

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How many milliliters of 12.0 M hydrochloric acid ( $H C l$ $HCl$ ) is required to prepare 0.75 L of a 0.25 M solution of $H C l$ $HCl$ ?

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Answer 1 · 2016-05-28T18:12:39

16mL

Explanation:

We have to use the titration formula:
$M_{a} V_{a} = M_{b} V_{b}$ $M_aV_a=M_bV_b$
Now just plug it in.
$(12) (x) = (.75) (.25)$ $(12)(x)=(.75)(.25)$
$12 x = .1875$ $12x = .1875$
$x = 0.015625$ $x= 0.015625$ liters
To convert liter to mL, multiply it by 1000, since 1 L= 1000 mL
Therefore, the answer rounded is about 16 mL

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How many milliliters of 12.0 M hydrochloric acid ( $H C l$ $HCl$ ) is required to prepare 0.75 L of a 0.25 M solution of $H C l$ $HCl$ ?

1 Answer

Explanation:

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How many milliliters of 12.0 M hydrochloric acid ( $H C l$ $HCl$ ) is required to prepare 0.75 L of a 0.25 M solution of $H C l$ $HCl$ ?