How do you solve ${cos}^{2} x - cos x = 0$ $cos^2x - cosx = 0$ ?

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How do you solve ${cos}^{2} x - cos x = 0$ $cos^2x - cosx = 0$ ?

1 Answer

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Answer 1 · 2016-05-28T23:30:24

$x = 0^{o}$ $x=0^o$ ; $x = 90^{o}$ $x=90^o$

Explanation:

${cos}^{2} x - cos x = 0$ $Cos^2 x-Cos x=0$
$cos x (1 - cos x) = 0$ $Cos x(1-Cos x)=0$
$cos x = 0; cos x = 1$ $Cosx=0 ; Cos x=1$
$x = 0^{o}$ $x=0^o$ ; $x = 90^{o}$ $x=90^o$

Test:
(a)
$x = 0^{o}$ $x=0^o$
${cos}^{2} 0$ $Cos^2 0$ - $cos 0$ $Cos 0$
$1^{2} - 1 = 0$ $1^2 -1 = 0$
(b)
$x = 0^{o}$ $x=0^o$
${cos}^{2} 90$ $Cos^2 90$ - $cos 90$ $Cos 90$
$0^{2} - 0 = 0$ $0^2 -0= 0$

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How do you solve ${cos}^{2} x - cos x = 0$ $cos^2x - cosx = 0$ ?

1 Answer

Explanation:

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How do you solve cos^2x - cosx = 0cos2x−cosx=0cos^2x - cosx = 0?

1 Answer

Explanation:

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How do you solve ${cos}^{2} x - cos x = 0$ $cos^2x - cosx = 0$ ?