How do you evaluate ${sec}^{2} (- \frac{π}{4})$ $sec^2 (-pi/4)$ ?

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How do you evaluate ${sec}^{2} (- \frac{π}{4})$ $sec^2 (-pi/4)$ ?

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Answer 1 · 2016-05-28T23:43:01

2

Explanation:

${sec}^{2} (- \frac{π}{4})$ $Sec^2(-(pi)/4)$ = $\frac{1}{{sin}^{2} (- \frac{π}{4})}$ $1/(Sin^2(-pi/4))$
$= \frac{1}{- \frac{1}{\sqrt{2}}} \times \frac{1}{- \frac{1}{\sqrt{2}}}$ $=1/(-1/sqrt2)xx1/(-1/sqrt2)$
$= (- \sqrt{2}) \times (- \sqrt{2})$ $=(-sqrt2)xx(-sqrt2)$
$2$ $2$

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How do you evaluate ${sec}^{2} (- \frac{π}{4})$ $sec^2 (-pi/4)$ ?

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