How do you solve $13 x - 4 (2 x - 5) = 15$ $13x-4(2x-5)=15$ ?

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Answer 1 · 2016-05-29T16:46:13

$x = - 1$ $x = - 1$

$13 x - 4 (2 x - 5) = 15$ $13x - 4 ( 2x - 5) = 15$

$13 x + (- 4) \cdot (2 x) + (- 4) \cdot (- 5) = 15$ $13x + (- 4) * ( 2x) + (-4) * ( - 5) = 15$

$13 x - 8 x + 20 = 15$ $13x -8x + 20 = 15$

$5 x + 20 = 15$ $5x + 20 = 15$

$5 x = 15 - 20$ $5x = 15 - 20$

$5 x = - 5$ $5x = - 5$

$x = - \frac{5}{5}$ $x = - 5 /5$

$x = - 1$ $x = - 1$

Answer 2 · 2018-08-05T02:08:50

$x = - 1$ $x=-1$

We can start by distributing the $- 4$ $-4$ on the left side to get

$13 x - 8 x + 20 = 15$ $13x-8x+20=15$

We can simplify the $x$ $x$ terms on the right to get

$5 x + 20 = 15$ $5x+20=15$

Next, to further isolate the $x$ $x$ term, we can subtract $20$ $20$ from both sides. We now have

$5 x = - 5$ $5x=-5$

Our last step would be to divide both sides by $5$ $5$ . We get

$x = - 1$ $x=-1$

Hope this helps!

How do you solve 13x−4(2x−5)=1513x-4(2x-5)=15?