How do you convert # (2, -3)# to polar form?

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Answer 1 · 2016-05-31T01:30:56

Polar Form: (3.6,-56.3)

Polar format: #(r, theta)#

#r=sqrt(x^2+y^2#

#theta=tan^-1(y/x)#

Apply both formulas when going from Cartesian -> Polar

#sqrt(2^2+(-3)^2) = sqrt(13) = 3.6#

#theta = tan^-1 ((-3)/2) ~~ -"0.98 radians"#

Thus our answer of:

Polar format of #(2,-3)# Cartesian:

#(3.6, 0.98)#