How do you simplify $5 \frac{2^{3} + 4}{\sqrt{36}} \times 7$ $5(2^3+4)/sqrt 36 times 7$ using PEMDAS?

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How do you simplify $5 \frac{2^{3} + 4}{\sqrt{36}} \times 7$ $5(2^3+4)/sqrt 36 times 7$ using PEMDAS?

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Answer 1 · 2016-05-31T04:05:10

$70$ $70$

Explanation:

First, there are no explicitly written parentheses, but the numerator of the fraction must be computed first for the problem to make sense. This term is calculated by first computing $2^{3}$ $2^3$ then adding four. The problem is then reduced to:

$5 \times \frac{12}{\sqrt{36}} \times 7$ $5 xx 12/sqrt(36) xx7$

Next compute any terms with exponents. There is one exponent left which is hidden in the denominator. Note that $\sqrt{36} = 36^{\frac{1}{2}}$ $sqrt(36)=36^(1/2)$ . Hence the problem is now

$5 \times \frac{12}{6} \times 7$ $5 xx 12/6 xx7$

Finally, perform all of the multiplication and division by moving left to right.

$5 \times \frac{12}{6} \times 7 = \frac{60}{6} \times 7 = 10 \times 7 = 70$ $5 xx 12/6 xx 7=60/6 xx 7=10 xx 7=70$

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How do you simplify $5 \frac{2^{3} + 4}{\sqrt{36}} \times 7$ $5(2^3+4)/sqrt 36 times 7$ using PEMDAS?

1 Answer

Explanation:

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