How do you simplify ${(- m^{2} n^{4} \times - m n^{- 2})}^{5}$ $(-m^2n^4 times -mn^-2)^5$ ?

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Answer 1 · 2016-05-31T04:41:26

$m^{15} n^{10}$ $m^15n^10$

First multiply the two terms in the parentheses keeping in mind that you add the exponents of terms with the same base.

${({(- 1)}^{2} m^{2 + 1} n^{4 - 2})}^{5} = {(m^{3} n^{2})}^{5}$ $((-1)^2m^(2+1)n^(4-2))^5=(m^3n^2)^5$

Now distribute the fifth power to each term in the parentheses keeping in mind that you multiply each term by the power.

$m^{3 \cdot 5} n^{2 \cdot 5} = m^{15} n^{10}$ $m^(3*5)n^(2*5)=m^15n^10$

How do you simplify (−m2n4×−mn−2)5 (-m^2n^4 times -mn^-2)^5?