We have a half cylinder roof of radius #r# and height #r# mounted on top of four rectangular walls of height #h#. We have #200π# #m^2# of plastic sheet to be used in the construction of this structure. What is the value of #r# that allows maximum volume?
1 Answer
Explanation:
Let me restate the question as I understand it.
Provided the surface area of this object is
Plan
Knowing the surface area, we can represent a height
This function needs to be maximized using
Surface area contains:
4 walls that form a side surface of a parallelepiped with a perimeter of a base
1 roof, half of a side surface of a cylinder of a radius
2 sides of the roof, semicircles of a radius
The resulting total surface area of an object is
Knowing this to be equal to
The volume of this object has two parts: Below the roof and within the roof.
Below the roof we have a parallelepiped with area of the base
Within the roof we have half a cylinder with radius
We have to maximize the function
that looks like this (not to scale)
graph{2x-0.6x^3 [-5.12, 5.114, -2.56, 2.56]}
This function reaches its maximum when it's derivative equals to zero for a positive argument.
In the area of
That is the radius that gives the largest volume, given the surface area and a shape of an object.