How do you differentiate $(\sqrt{x}) (x - 1)$ $(sqrt x)(x-1)$ ?

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How do you differentiate $(\sqrt{x}) (x - 1)$ $(sqrt x)(x-1)$ ?

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Answer 1 · 2016-06-01T09:47:59

$x^{\frac{3}{2}} - x^{\frac{1}{2}}, \frac{d}{d x}$ $x^(3/2)-x^(1/2) ,(d)/(dx)$

= $\frac{3}{2} x^{\frac{1}{2}} - \frac{1}{2 x^{\frac{1}{2}}}$ $3/2x^(1/2)-1/(2x^(1/2)$

Explanation:

By expanding the equation, you add the indices together of root x and x, which is 0.5 plus 1 which = 1.5 or 3/2. Then obviously root x times 1 is root x. You then differentiate the equation. Done!

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How do you differentiate $(\sqrt{x}) (x - 1)$ $(sqrt x)(x-1)$ ?

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How do you differentiate $(\sqrt{x}) (x - 1)$ $(sqrt x)(x-1)$ ?